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117148183993 is a prime number
BaseRepresentation
bin110110100011010010…
…0110110110110111001
3102012101020222100101101
41231012210312312321
53404404413341433
6125452300051401
711315020064011
oct1550644666671
9365336870341
10117148183993
1145756106595
121a854833b61
13b07c417289
1459546b4c41
1530a993307d
hex1b46936db9

117148183993 has 2 divisors, whose sum is σ = 117148183994. Its totient is φ = 117148183992.

The previous prime is 117148183973. The next prime is 117148184003. The reversal of 117148183993 is 399381841711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87372265744 + 29775918249 = 295588^2 + 172557^2 .

It is an emirp because it is prime and its reverse (399381841711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 117148183993 - 225 = 117114629561 is a prime.

It is not a weakly prime, because it can be changed into another prime (117148183973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58574091996 + 58574091997.

It is an arithmetic number, because the mean of its divisors is an integer number (58574091997).

Almost surely, 2117148183993 is an apocalyptic number.

It is an amenable number.

117148183993 is a deficient number, since it is larger than the sum of its proper divisors (1).

117148183993 is an equidigital number, since it uses as much as digits as its factorization.

117148183993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1306368, while the sum is 55.

The spelling of 117148183993 in words is "one hundred seventeen billion, one hundred forty-eight million, one hundred eighty-three thousand, nine hundred ninety-three".