Base | Representation |
---|---|
bin | 11010101000110010110101… |
… | …011101000001110000011011 |
3 | 120100210200021012010011121111 |
4 | 122220302311131001300123 |
5 | 110323411431444014123 |
6 | 1053055052042121151 |
7 | 33450664644520621 |
oct | 3250626535016033 |
9 | 510720235104544 |
10 | 117152572251163 |
11 | 34368143968a99 |
12 | 11180b534b01b7 |
13 | 504a595054a37 |
14 | 20d03013c5511 |
15 | d8261973e90d |
hex | 6a8cb5741c1b |
117152572251163 has 2 divisors, whose sum is σ = 117152572251164. Its totient is φ = 117152572251162.
The previous prime is 117152572251149. The next prime is 117152572251359. The reversal of 117152572251163 is 361152275251711.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117152572251163 - 25 = 117152572251131 is a prime.
It is not a weakly prime, because it can be changed into another prime (117152572251863) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58576286125581 + 58576286125582.
It is an arithmetic number, because the mean of its divisors is an integer number (58576286125582).
Almost surely, 2117152572251163 is an apocalyptic number.
117152572251163 is a deficient number, since it is larger than the sum of its proper divisors (1).
117152572251163 is an equidigital number, since it uses as much as digits as its factorization.
117152572251163 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 882000, while the sum is 49.
The spelling of 117152572251163 in words is "one hundred seventeen trillion, one hundred fifty-two billion, five hundred seventy-two million, two hundred fifty-one thousand, one hundred sixty-three".
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