Base | Representation |
---|---|
bin | 10101110100101100… |
… | …10010100010111001 |
3 | 1010020112100201211201 |
4 | 22322112102202321 |
5 | 142443340334042 |
6 | 5214333454201 |
7 | 563225150233 |
oct | 127226224271 |
9 | 33215321751 |
10 | 11716339897 |
11 | 4a72628639 |
12 | 232b941361 |
13 | 1149468202 |
14 | 7d209d253 |
15 | 4888dd1b7 |
hex | 2ba5928b9 |
11716339897 has 2 divisors, whose sum is σ = 11716339898. Its totient is φ = 11716339896.
The previous prime is 11716339889. The next prime is 11716339907. The reversal of 11716339897 is 79893361711.
11716339897 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11019960576 + 696379321 = 104976^2 + 26389^2 .
It is a cyclic number.
It is not a de Polignac number, because 11716339897 - 23 = 11716339889 is a prime.
It is not a weakly prime, because it can be changed into another prime (11716331897) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5858169948 + 5858169949.
It is an arithmetic number, because the mean of its divisors is an integer number (5858169949).
Almost surely, 211716339897 is an apocalyptic number.
It is an amenable number.
11716339897 is a deficient number, since it is larger than the sum of its proper divisors (1).
11716339897 is an equidigital number, since it uses as much as digits as its factorization.
11716339897 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1714608, while the sum is 55.
The spelling of 11716339897 in words is "eleven billion, seven hundred sixteen million, three hundred thirty-nine thousand, eight hundred ninety-seven".
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