Base | Representation |
---|---|
bin | 1010101010001010101100… |
… | …1010101101110100010011 |
3 | 1112111101012001210202112011 |
4 | 2222202223022231310103 |
5 | 3014003110334342111 |
6 | 40531514500243351 |
7 | 2316465121403362 |
oct | 252425312556423 |
9 | 45441161722464 |
10 | 11719542496531 |
11 | 3809259236491 |
12 | 13933ab0a0557 |
13 | 6701c05427bc |
14 | 2c732c0ad7d9 |
15 | 154cbb25b021 |
hex | aa8ab2add13 |
11719542496531 has 2 divisors, whose sum is σ = 11719542496532. Its totient is φ = 11719542496530.
The previous prime is 11719542496483. The next prime is 11719542496549. The reversal of 11719542496531 is 13569424591711.
11719542496531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11719542496531 - 221 = 11719540399379 is a prime.
It is a super-2 number, since 2×117195424965312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11719542496561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5859771248265 + 5859771248266.
It is an arithmetic number, because the mean of its divisors is an integer number (5859771248266).
Almost surely, 211719542496531 is an apocalyptic number.
11719542496531 is a deficient number, since it is larger than the sum of its proper divisors (1).
11719542496531 is an equidigital number, since it uses as much as digits as its factorization.
11719542496531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8164800, while the sum is 58.
The spelling of 11719542496531 in words is "eleven trillion, seven hundred nineteen billion, five hundred forty-two million, four hundred ninety-six thousand, five hundred thirty-one".
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