Base | Representation |
---|---|
bin | 10001000011100000001… |
… | …110110110001010111001 |
3 | 11011001010012202210220221 |
4 | 101003200032312022321 |
5 | 123200220212432133 |
6 | 2254223423220041 |
7 | 150450036630235 |
oct | 21034016661271 |
9 | 4131105683827 |
10 | 1171993092793 |
11 | 412048602196 |
12 | 16b182147621 |
13 | 8669811c073 |
14 | 40a20a9b5c5 |
15 | 2074605ca2d |
hex | 110e03b62b9 |
1171993092793 has 2 divisors, whose sum is σ = 1171993092794. Its totient is φ = 1171993092792.
The previous prime is 1171993092779. The next prime is 1171993092841. The reversal of 1171993092793 is 3972903991711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1111017186304 + 60975906489 = 1054048^2 + 246933^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1171993092793 is a prime.
It is not a weakly prime, because it can be changed into another prime (1171993092733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 585996546396 + 585996546397.
It is an arithmetic number, because the mean of its divisors is an integer number (585996546397).
Almost surely, 21171993092793 is an apocalyptic number.
It is an amenable number.
1171993092793 is a deficient number, since it is larger than the sum of its proper divisors (1).
1171993092793 is an equidigital number, since it uses as much as digits as its factorization.
1171993092793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5786802, while the sum is 61.
The spelling of 1171993092793 in words is "one trillion, one hundred seventy-one billion, nine hundred ninety-three million, ninety-two thousand, seven hundred ninety-three".
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