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117223617474433 is a prime number
BaseRepresentation
bin11010101001110101000000…
…000101000010111110000001
3120101001110122110020110021001
4122221311000011002332001
5110331042432033140213
61053151441511532001
733456061343122501
oct3251650005027601
9511043573213231
10117223617474433
1134395291061848
121119288038a001
1350541a7bb16a2
1420d3920b5ba01
15d843c69b61dd
hex6a9d40142f81

117223617474433 has 2 divisors, whose sum is σ = 117223617474434. Its totient is φ = 117223617474432.

The previous prime is 117223617474371. The next prime is 117223617474499. The reversal of 117223617474433 is 334474716322711.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107040191916529 + 10183425557904 = 10346023^2 + 3191148^2 .

It is an emirp because it is prime and its reverse (334474716322711) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-117223617474433 is a prime.

It is not a weakly prime, because it can be changed into another prime (117223617478433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58611808737216 + 58611808737217.

It is an arithmetic number, because the mean of its divisors is an integer number (58611808737217).

Almost surely, 2117223617474433 is an apocalyptic number.

It is an amenable number.

117223617474433 is a deficient number, since it is larger than the sum of its proper divisors (1).

117223617474433 is an equidigital number, since it uses as much as digits as its factorization.

117223617474433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14224896, while the sum is 55.

The spelling of 117223617474433 in words is "one hundred seventeen trillion, two hundred twenty-three billion, six hundred seventeen million, four hundred seventy-four thousand, four hundred thirty-three".