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11726045537 is a prime number
BaseRepresentation
bin10101110101110110…
…10100000101100001
31010021012121211110212
422322323110011201
5143003331424122
65215321503505
7563403512453
oct127273240541
933235554425
1011726045537
114a78057628
122333041b95
13114b485aab
147d34a82d3
154896a8ce2
hex2baed4161

11726045537 has 2 divisors, whose sum is σ = 11726045538. Its totient is φ = 11726045536.

The previous prime is 11726045503. The next prime is 11726045621. The reversal of 11726045537 is 73554062711.

11726045537 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7742416081 + 3983629456 = 87991^2 + 63116^2 .

It is a cyclic number.

It is not a de Polignac number, because 11726045537 - 214 = 11726029153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11726045494 and 11726045503.

It is not a weakly prime, because it can be changed into another prime (11726045437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5863022768 + 5863022769.

It is an arithmetic number, because the mean of its divisors is an integer number (5863022769).

Almost surely, 211726045537 is an apocalyptic number.

It is an amenable number.

11726045537 is a deficient number, since it is larger than the sum of its proper divisors (1).

11726045537 is an equidigital number, since it uses as much as digits as its factorization.

11726045537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 176400, while the sum is 41.

The spelling of 11726045537 in words is "eleven billion, seven hundred twenty-six million, forty-five thousand, five hundred thirty-seven".