Base | Representation |
---|---|
bin | 1010101010110011100100… |
… | …0010011011101101110001 |
3 | 1112112102111121001000000221 |
4 | 2222230321002123231301 |
5 | 3014143042212440442 |
6 | 40540531220213041 |
7 | 2320334016062632 |
oct | 252547102335561 |
9 | 45472447030027 |
10 | 11730512624497 |
11 | 3812978620a47 |
12 | 1395550b3a181 |
13 | 67124b20b494 |
14 | 2c7a8d005889 |
15 | 15520e399467 |
hex | aab3909bb71 |
11730512624497 has 2 divisors, whose sum is σ = 11730512624498. Its totient is φ = 11730512624496.
The previous prime is 11730512624461. The next prime is 11730512624503. The reversal of 11730512624497 is 79442621503711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8087334942976 + 3643177681521 = 2843824^2 + 1908711^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11730512624497 is a prime.
It is not a weakly prime, because it can be changed into another prime (11730512624297) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5865256312248 + 5865256312249.
It is an arithmetic number, because the mean of its divisors is an integer number (5865256312249).
Almost surely, 211730512624497 is an apocalyptic number.
It is an amenable number.
11730512624497 is a deficient number, since it is larger than the sum of its proper divisors (1).
11730512624497 is an equidigital number, since it uses as much as digits as its factorization.
11730512624497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2540160, while the sum is 52.
The spelling of 11730512624497 in words is "eleven trillion, seven hundred thirty billion, five hundred twelve million, six hundred twenty-four thousand, four hundred ninety-seven".
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