Base | Representation |
---|---|
bin | 1010101010111101000110… |
… | …0110100110001111110011 |
3 | 1112112200002222102000200021 |
4 | 2222233101212212033303 |
5 | 3014213312443213101 |
6 | 40542033213504311 |
7 | 2320454316342415 |
oct | 252572146461763 |
9 | 45480088360607 |
10 | 11733072241651 |
11 | 3813a71444222 |
12 | 1395b461a2097 |
13 | 6715685b2547 |
14 | 2c7c52d349b5 |
15 | 15530de4e5a1 |
hex | aabd19a63f3 |
11733072241651 has 2 divisors, whose sum is σ = 11733072241652. Its totient is φ = 11733072241650.
The previous prime is 11733072241643. The next prime is 11733072241687. The reversal of 11733072241651 is 15614227033711.
It is a weak prime.
It is an emirp because it is prime and its reverse (15614227033711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11733072241651 - 23 = 11733072241643 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11733072241598 and 11733072241607.
It is not a weakly prime, because it can be changed into another prime (11733072244651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5866536120825 + 5866536120826.
It is an arithmetic number, because the mean of its divisors is an integer number (5866536120826).
Almost surely, 211733072241651 is an apocalyptic number.
11733072241651 is a deficient number, since it is larger than the sum of its proper divisors (1).
11733072241651 is an equidigital number, since it uses as much as digits as its factorization.
11733072241651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 211680, while the sum is 43.
The spelling of 11733072241651 in words is "eleven trillion, seven hundred thirty-three billion, seventy-two million, two hundred forty-one thousand, six hundred fifty-one".
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