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11733072241651 is a prime number
BaseRepresentation
bin1010101010111101000110…
…0110100110001111110011
31112112200002222102000200021
42222233101212212033303
53014213312443213101
640542033213504311
72320454316342415
oct252572146461763
945480088360607
1011733072241651
113813a71444222
121395b461a2097
136715685b2547
142c7c52d349b5
1515530de4e5a1
hexaabd19a63f3

11733072241651 has 2 divisors, whose sum is σ = 11733072241652. Its totient is φ = 11733072241650.

The previous prime is 11733072241643. The next prime is 11733072241687. The reversal of 11733072241651 is 15614227033711.

It is a weak prime.

It is an emirp because it is prime and its reverse (15614227033711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11733072241651 - 23 = 11733072241643 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11733072241598 and 11733072241607.

It is not a weakly prime, because it can be changed into another prime (11733072244651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5866536120825 + 5866536120826.

It is an arithmetic number, because the mean of its divisors is an integer number (5866536120826).

Almost surely, 211733072241651 is an apocalyptic number.

11733072241651 is a deficient number, since it is larger than the sum of its proper divisors (1).

11733072241651 is an equidigital number, since it uses as much as digits as its factorization.

11733072241651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 211680, while the sum is 43.

The spelling of 11733072241651 in words is "eleven trillion, seven hundred thirty-three billion, seventy-two million, two hundred forty-one thousand, six hundred fifty-one".