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117393000000 = 26356109359
BaseRepresentation
bin110110101010100101…
…0110000011001000000
3102020000022122021210220
41231111022300121000
53410410102000000
6125532443223040
711324052015213
oct1552512603100
9366008567726
10117393000000
1145871319471
121a902817a80
13b0bb063213
14597900177a
1530c11911a0
hex1b552b0640

117393000000 has 392 divisors, whose sum is σ = 392901220800. Its totient is φ = 30931200000.

The previous prime is 117392999989. The next prime is 117393000029. The reversal of 117393000000 is 393711.

It is a super-2 number, since 2×1173930000002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 326999821 + ... + 327000179.

Almost surely, 2117393000000 is an apocalyptic number.

117393000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 117393000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196450610400).

117393000000 is an abundant number, since it is smaller than the sum of its proper divisors (275508220800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

117393000000 is an frugal number, since it uses more digits than its factorization.

117393000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 513 (or 478 counting only the distinct ones).

The product of its (nonzero) digits is 567, while the sum is 24.

Adding to 117393000000 its reverse (393711), we get a palindrome (117393393711).

The spelling of 117393000000 in words is "one hundred seventeen billion, three hundred ninety-three million", and thus it is an aban number.