117400411433 has 4 divisors (see below), whose sum is σ = 117418793220. Its totient is φ = 117382029648.

The previous prime is 117400411283. The next prime is 117400411477. The reversal of 117400411433 is 334114004711.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 51796297744 + 65604113689 = 227588^2 + 256133^2 .

It is a cyclic number.

It is not a de Polignac number, because 117400411433 - 2²⁴ = 117383634217 is a prime.

It is a super-2 number, since 2×117400411433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 117400411396 and 117400411405.

It is not an unprimeable number, because it can be changed into a prime (117400413433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9181310 + ... + 9194087.

It is an arithmetic number, because the mean of its divisors is an integer number (29354698305).

Almost surely, 2^117400411433 is an apocalyptic number.

It is an amenable number.

117400411433 is a deficient number, since it is larger than the sum of its proper divisors (18381787).

117400411433 is an equidigital number, since it uses as much as digits as its factorization.

117400411433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18381786.

The product of its (nonzero) digits is 4032, while the sum is 29.

The spelling of 117400411433 in words is "one hundred seventeen billion, four hundred million, four hundred eleven thousand, four hundred thirty-three".