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117400411477 is a prime number
BaseRepresentation
bin110110101010110011…
…1000001110101010101
3102020000211120211110001
41231111213001311111
53410414001131402
6125533310131301
711324202014056
oct1552547016525
9366024524401
10117400411477
1145875520858
121a9051b0b31
13b0bc7597cb
145979db072d
1530c1b57187
hex1b559c1d55

117400411477 has 2 divisors, whose sum is σ = 117400411478. Its totient is φ = 117400411476.

The previous prime is 117400411283. The next prime is 117400411481. The reversal of 117400411477 is 774114004711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63378566001 + 54021845476 = 251751^2 + 232426^2 .

It is an emirp because it is prime and its reverse (774114004711) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-117400411477 is a prime.

It is a super-2 number, since 2×1174004114772 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117400421477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58700205738 + 58700205739.

It is an arithmetic number, because the mean of its divisors is an integer number (58700205739).

Almost surely, 2117400411477 is an apocalyptic number.

It is an amenable number.

117400411477 is a deficient number, since it is larger than the sum of its proper divisors (1).

117400411477 is an equidigital number, since it uses as much as digits as its factorization.

117400411477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21952, while the sum is 37.

The spelling of 117400411477 in words is "one hundred seventeen billion, four hundred million, four hundred eleven thousand, four hundred seventy-seven".