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117400411283 is a prime number
BaseRepresentation
bin110110101010110011…
…1000001110010010011
3102020000211120211011212
41231111213001302103
53410414001130113
6125533310130335
711324202013361
oct1552547016223
9366024524155
10117400411283
11458755206a1
121a9051b09ab
13b0bc7596ac
145979db0631
1530c1b570a8
hex1b559c1c93

117400411283 has 2 divisors, whose sum is σ = 117400411284. Its totient is φ = 117400411282.

The previous prime is 117400411279. The next prime is 117400411477. The reversal of 117400411283 is 382114004711.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 117400411283 - 22 = 117400411279 is a prime.

It is not a weakly prime, because it can be changed into another prime (117400411223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58700205641 + 58700205642.

It is an arithmetic number, because the mean of its divisors is an integer number (58700205642).

Almost surely, 2117400411283 is an apocalyptic number.

117400411283 is a deficient number, since it is larger than the sum of its proper divisors (1).

117400411283 is an equidigital number, since it uses as much as digits as its factorization.

117400411283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 32.

Adding to 117400411283 its reverse (382114004711), we get a palindrome (499514415994).

The spelling of 117400411283 in words is "one hundred seventeen billion, four hundred million, four hundred eleven thousand, two hundred eighty-three".