Base | Representation |
---|---|
bin | 110110101101011100… |
… | …0111110000001101001 |
3 | 102020021000021121210221 |
4 | 1231122320332001221 |
5 | 3411104141004203 |
6 | 125550153010041 |
7 | 11326326012211 |
oct | 1553270760151 |
9 | 366230247727 |
10 | 117489000553 |
11 | 45910529071 |
12 | 1a92a9b3921 |
13 | b104c06492 |
14 | 5987a71241 |
15 | 30c9805abd |
hex | 1b5ae3e069 |
117489000553 has 2 divisors, whose sum is σ = 117489000554. Its totient is φ = 117489000552.
The previous prime is 117489000523. The next prime is 117489000593. The reversal of 117489000553 is 355000984711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114804413584 + 2684586969 = 338828^2 + 51813^2 .
It is a cyclic number.
It is not a de Polignac number, because 117489000553 - 25 = 117489000521 is a prime.
It is not a weakly prime, because it can be changed into another prime (117489000523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58744500276 + 58744500277.
It is an arithmetic number, because the mean of its divisors is an integer number (58744500277).
Almost surely, 2117489000553 is an apocalyptic number.
117489000553 is the 183217-th centered heptagonal number.
It is an amenable number.
117489000553 is a deficient number, since it is larger than the sum of its proper divisors (1).
117489000553 is an equidigital number, since it uses as much as digits as its factorization.
117489000553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 43.
The spelling of 117489000553 in words is "one hundred seventeen billion, four hundred eighty-nine million, five hundred fifty-three", and thus it is an aban number.
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