Base | Representation |
---|---|
bin | 10101111000101001… |
… | …00011001001010001 |
3 | 1010022211122021221121 |
4 | 22330110203021101 |
5 | 143030324004113 |
6 | 5221515122241 |
7 | 564106401244 |
oct | 127424431121 |
9 | 33284567847 |
10 | 11749438033 |
11 | 4a8a284773 |
12 | 233aa43381 |
13 | 11532863c8 |
14 | 7d663725b |
15 | 48b779e8d |
hex | 2bc523251 |
11749438033 has 2 divisors, whose sum is σ = 11749438034. Its totient is φ = 11749438032.
The previous prime is 11749438007. The next prime is 11749438081. The reversal of 11749438033 is 33083494711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6506519569 + 5242918464 = 80663^2 + 72408^2 .
It is a cyclic number.
It is not a de Polignac number, because 11749438033 - 213 = 11749429841 is a prime.
It is not a weakly prime, because it can be changed into another prime (11749438333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5874719016 + 5874719017.
It is an arithmetic number, because the mean of its divisors is an integer number (5874719017).
Almost surely, 211749438033 is an apocalyptic number.
It is an amenable number.
11749438033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11749438033 is an equidigital number, since it uses as much as digits as its factorization.
11749438033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 43.
The spelling of 11749438033 in words is "eleven billion, seven hundred forty-nine million, four hundred thirty-eight thousand, thirty-three".
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