Base | Representation |
---|---|
bin | 10101111001010110… |
… | …10011000000100111 |
3 | 1010100020212020221200 |
4 | 22330223103000213 |
5 | 143033340320010 |
6 | 5222251013543 |
7 | 564211155603 |
oct | 127453230047 |
9 | 33306766850 |
10 | 11755401255 |
11 | 4a92687a54 |
12 | 2340a3a2b3 |
13 | 1154593740 |
14 | 7d734a503 |
15 | 48c056cc0 |
hex | 2bcad3027 |
11755401255 has 24 divisors (see below), whose sum is σ = 21943416768. Its totient is φ = 5787274176.
The previous prime is 11755401199. The next prime is 11755401293. The reversal of 11755401255 is 55210455711.
11755401255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11755401255 - 27 = 11755401127 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10046767 + ... + 10047936.
It is an arithmetic number, because the mean of its divisors is an integer number (914309032).
Almost surely, 211755401255 is an apocalyptic number.
11755401255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11755401255 is a deficient number, since it is larger than the sum of its proper divisors (10188015513).
11755401255 is a wasteful number, since it uses less digits than its factorization.
11755401255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20094727 (or 20094724 counting only the distinct ones).
The product of its (nonzero) digits is 35000, while the sum is 36.
Adding to 11755401255 its reverse (55210455711), we get a palindrome (66965856966).
The spelling of 11755401255 in words is "eleven billion, seven hundred fifty-five million, four hundred one thousand, two hundred fifty-five".
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