Base | Representation |
---|---|
bin | 1010101100010000010010… |
… | …0001101110011110111011 |
3 | 1112121210202010201210020112 |
4 | 2223010010201232132323 |
5 | 3020100030232023123 |
6 | 41000205030014535 |
7 | 2322204543364544 |
oct | 253040441563673 |
9 | 45553663653215 |
10 | 11755401439163 |
11 | 382248a716868 |
12 | 139a3381a744b |
13 | 6736b66b5c55 |
14 | 2c8d706c94cb |
15 | 155bb9407d78 |
hex | ab10486e7bb |
11755401439163 has 2 divisors, whose sum is σ = 11755401439164. Its totient is φ = 11755401439162.
The previous prime is 11755401439129. The next prime is 11755401439267. The reversal of 11755401439163 is 36193410455711.
11755401439163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11755401439163 - 218 = 11755401177019 is a prime.
It is not a weakly prime, because it can be changed into another prime (11755401439123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5877700719581 + 5877700719582.
It is an arithmetic number, because the mean of its divisors is an integer number (5877700719582).
Almost surely, 211755401439163 is an apocalyptic number.
11755401439163 is a deficient number, since it is larger than the sum of its proper divisors (1).
11755401439163 is an equidigital number, since it uses as much as digits as its factorization.
11755401439163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1360800, while the sum is 50.
The spelling of 11755401439163 in words is "eleven trillion, seven hundred fifty-five billion, four hundred one million, four hundred thirty-nine thousand, one hundred sixty-three".
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