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11761225420657 is a prime number
BaseRepresentation
bin1010101100100101111110…
…1010011100111101110001
31112122100210000120200220211
42223021133222130331301
53020143442201430112
641003010554104121
72322502062406456
oct253113752347561
945570700520824
1011761225420657
1138249a9154309
12139b4a271b041
1367410417314b
142c9363d9982d
15155e0a8720a7
hexab25fa9cf71

11761225420657 has 2 divisors, whose sum is σ = 11761225420658. Its totient is φ = 11761225420656.

The previous prime is 11761225420619. The next prime is 11761225420661. The reversal of 11761225420657 is 75602452216711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10849322656561 + 911902764096 = 3293831^2 + 954936^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11761225420657 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11761225420657.

It is not a weakly prime, because it can be changed into another prime (11761225420757) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5880612710328 + 5880612710329.

It is an arithmetic number, because the mean of its divisors is an integer number (5880612710329).

Almost surely, 211761225420657 is an apocalyptic number.

It is an amenable number.

11761225420657 is a deficient number, since it is larger than the sum of its proper divisors (1).

11761225420657 is an equidigital number, since it uses as much as digits as its factorization.

11761225420657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1411200, while the sum is 49.

The spelling of 11761225420657 in words is "eleven trillion, seven hundred sixty-one billion, two hundred twenty-five million, four hundred twenty thousand, six hundred fifty-seven".