Base | Representation |
---|---|
bin | 10101111010011101… |
… | …11001000010000001 |
3 | 1010100220102022101001 |
4 | 22331032321002001 |
5 | 143043232411113 |
6 | 5223223012001 |
7 | 564353400205 |
oct | 127516710201 |
9 | 33326368331 |
10 | 11764732033 |
11 | 4a9798033a |
12 | 2343b9a001 |
13 | 11564ac802 |
14 | 7d8698b05 |
15 | 48cc9b7dd |
hex | 2bd3b9081 |
11764732033 has 2 divisors, whose sum is σ = 11764732034. Its totient is φ = 11764732032.
The previous prime is 11764732027. The next prime is 11764732087. The reversal of 11764732033 is 33023746711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9661317264 + 2103414769 = 98292^2 + 45863^2 .
It is an emirp because it is prime and its reverse (33023746711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11764732033 - 221 = 11762634881 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11764731983 and 11764732001.
It is not a weakly prime, because it can be changed into another prime (11764735033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5882366016 + 5882366017.
It is an arithmetic number, because the mean of its divisors is an integer number (5882366017).
Almost surely, 211764732033 is an apocalyptic number.
It is an amenable number.
11764732033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11764732033 is an equidigital number, since it uses as much as digits as its factorization.
11764732033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63504, while the sum is 37.
The spelling of 11764732033 in words is "eleven billion, seven hundred sixty-four million, seven hundred thirty-two thousand, thirty-three".
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