Base | Representation |
---|---|
bin | 110110110011000000… |
… | …0111111010000111001 |
3 | 102020202000111111200011 |
4 | 1231212000333100321 |
5 | 3411444431332103 |
6 | 130020501341521 |
7 | 11334053353033 |
oct | 1554600772071 |
9 | 366660444604 |
10 | 117675652153 |
11 | 459a6924194 |
12 | 1a9814078a1 |
13 | b134798b07 |
14 | 59a477ac53 |
15 | 30dadc4d6d |
hex | 1b6603f439 |
117675652153 has 2 divisors, whose sum is σ = 117675652154. Its totient is φ = 117675652152.
The previous prime is 117675652117. The next prime is 117675652177. The reversal of 117675652153 is 351256576711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87797838249 + 29877813904 = 296307^2 + 172852^2 .
It is a cyclic number.
It is not a de Polignac number, because 117675652153 - 213 = 117675643961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 117675652097 and 117675652106.
It is not a weakly prime, because it can be changed into another prime (117675652753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58837826076 + 58837826077.
It is an arithmetic number, because the mean of its divisors is an integer number (58837826077).
Almost surely, 2117675652153 is an apocalyptic number.
It is an amenable number.
117675652153 is a deficient number, since it is larger than the sum of its proper divisors (1).
117675652153 is an equidigital number, since it uses as much as digits as its factorization.
117675652153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1323000, while the sum is 49.
The spelling of 117675652153 in words is "one hundred seventeen billion, six hundred seventy-five million, six hundred fifty-two thousand, one hundred fifty-three".
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