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118132107113 is a prime number
BaseRepresentation
bin110111000000100111…
…0001110011101101001
3102021220211101211011102
41232001032032131221
53413413304411423
6130134045011145
711351265225356
oct1560116163551
9367824354142
10118132107113
1146110549599
121aa8a253ab5
13b1a82158c7
145a0923962d
153115edac28
hex1b8138e769

118132107113 has 2 divisors, whose sum is σ = 118132107114. Its totient is φ = 118132107112.

The previous prime is 118132107053. The next prime is 118132107127. The reversal of 118132107113 is 311701231811.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92250697984 + 25881409129 = 303728^2 + 160877^2 .

It is a cyclic number.

It is not a de Polignac number, because 118132107113 - 214 = 118132090729 is a prime.

It is not a weakly prime, because it can be changed into another prime (118132307113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59066053556 + 59066053557.

It is an arithmetic number, because the mean of its divisors is an integer number (59066053557).

Almost surely, 2118132107113 is an apocalyptic number.

It is an amenable number.

118132107113 is a deficient number, since it is larger than the sum of its proper divisors (1).

118132107113 is an equidigital number, since it uses as much as digits as its factorization.

118132107113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 29.

Adding to 118132107113 its reverse (311701231811), we get a palindrome (429833338924).

The spelling of 118132107113 in words is "one hundred eighteen billion, one hundred thirty-two million, one hundred seven thousand, one hundred thirteen".