Base | Representation |
---|---|
bin | 1010101111101001000100… |
… | …1011000101100000010011 |
3 | 1112211100221210102211111221 |
4 | 2223322101023011200103 |
5 | 3022023220442311301 |
6 | 41043031350145511 |
7 | 2326334625223015 |
oct | 253722113054023 |
9 | 45740853384457 |
10 | 11813595666451 |
11 | 3845132857087 |
12 | 13a9679352297 |
13 | 67902bcb1677 |
14 | 2cbad14021b5 |
15 | 157473361da1 |
hex | abe912c5813 |
11813595666451 has 2 divisors, whose sum is σ = 11813595666452. Its totient is φ = 11813595666450.
The previous prime is 11813595666419. The next prime is 11813595666473. The reversal of 11813595666451 is 15466659531811.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11813595666451 - 25 = 11813595666419 is a prime.
It is a super-2 number, since 2×118135956664512 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11813595666451.
It is not a weakly prime, because it can be changed into another prime (11813595666251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5906797833225 + 5906797833226.
It is an arithmetic number, because the mean of its divisors is an integer number (5906797833226).
Almost surely, 211813595666451 is an apocalyptic number.
11813595666451 is a deficient number, since it is larger than the sum of its proper divisors (1).
11813595666451 is an equidigital number, since it uses as much as digits as its factorization.
11813595666451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23328000, while the sum is 61.
The spelling of 11813595666451 in words is "eleven trillion, eight hundred thirteen billion, five hundred ninety-five million, six hundred sixty-six thousand, four hundred fifty-one".
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