Base | Representation |
---|---|
bin | 1010101111101001000110… |
… | …1011000101011111110011 |
3 | 1112211100222101020000110221 |
4 | 2223322101223011133303 |
5 | 3022023230114230102 |
6 | 41043032250033511 |
7 | 2326335056431345 |
oct | 253722153053763 |
9 | 45740871200427 |
10 | 11813604055027 |
11 | 3845137566595 |
12 | 13a9680118897 |
13 | 67903095a918 |
14 | 2cbad2587295 |
15 | 157473e6c637 |
hex | abe91ac57f3 |
11813604055027 has 2 divisors, whose sum is σ = 11813604055028. Its totient is φ = 11813604055026.
The previous prime is 11813604055003. The next prime is 11813604055069. The reversal of 11813604055027 is 72055040631811.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11813604055027 - 223 = 11813595666419 is a prime.
It is a super-2 number, since 2×118136040550272 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11813604055427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5906802027513 + 5906802027514.
It is an arithmetic number, because the mean of its divisors is an integer number (5906802027514).
Almost surely, 211813604055027 is an apocalyptic number.
11813604055027 is a deficient number, since it is larger than the sum of its proper divisors (1).
11813604055027 is an equidigital number, since it uses as much as digits as its factorization.
11813604055027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 43.
Adding to 11813604055027 its reverse (72055040631811), we get a palindrome (83868644686838).
The spelling of 11813604055027 in words is "eleven trillion, eight hundred thirteen billion, six hundred four million, fifty-five thousand, twenty-seven".
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