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1184896138873 is a prime number
BaseRepresentation
bin10001001111100001010…
…100000011111001111001
311012021102110010110121111
4101033201110003321321
5123403131402420443
62304200032240321
7151414555000336
oct21174124037171
94167373113544
101184896138873
11417569a86737
121717833a00a1
13879733a5885
14414c65c998d
1520c4dc0c69d
hex113e1503e79

1184896138873 has 2 divisors, whose sum is σ = 1184896138874. Its totient is φ = 1184896138872.

The previous prime is 1184896138793. The next prime is 1184896138891. The reversal of 1184896138873 is 3788316984811.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 734229624384 + 450666514489 = 856872^2 + 671317^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1184896138873 is a prime.

It is a super-2 number, since 2×11848961388732 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1184896138799 and 1184896138808.

It is not a weakly prime, because it can be changed into another prime (1184896138973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 592448069436 + 592448069437.

It is an arithmetic number, because the mean of its divisors is an integer number (592448069437).

Almost surely, 21184896138873 is an apocalyptic number.

It is an amenable number.

1184896138873 is a deficient number, since it is larger than the sum of its proper divisors (1).

1184896138873 is an equidigital number, since it uses as much as digits as its factorization.

1184896138873 is an evil number, because the sum of its binary digits is even.

The product of its digits is 55738368, while the sum is 67.

The spelling of 1184896138873 in words is "one trillion, one hundred eighty-four billion, eight hundred ninety-six million, one hundred thirty-eight thousand, eight hundred seventy-three".