11849614433 has 2 divisors, whose sum is σ = 11849614434. Its totient is φ = 11849614432.

The previous prime is 11849614411. The next prime is 11849614451. The reversal of 11849614433 is 33441694811.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6330907489 + 5518706944 = 79567^2 + 74288^2 .

It is a cyclic number.

It is not a de Polignac number, because 11849614433 - 2⁸ = 11849614177 is a prime.

It is a super-2 number, since 2×11849614433² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11849614493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5924807216 + 5924807217.

It is an arithmetic number, because the mean of its divisors is an integer number (5924807217).

Almost surely, 2^11849614433 is an apocalyptic number.

It is an amenable number.

11849614433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11849614433 is an equidigital number, since it uses as much as digits as its factorization.

11849614433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 248832, while the sum is 44.

The spelling of 11849614433 in words is "eleven billion, eight hundred forty-nine million, six hundred fourteen thousand, four hundred thirty-three".