Base | Representation |
---|---|
bin | 10110001001100011… |
… | …10010100100101011 |
3 | 1010200201121200222011 |
4 | 23010301302210223 |
5 | 143323134234011 |
6 | 5243544140351 |
7 | 600451363504 |
oct | 130461624453 |
9 | 33621550864 |
10 | 11891321131 |
11 | 5052382628 |
12 | 237a4676b7 |
13 | 11767a28c1 |
14 | 80b40bbab |
15 | 498e54621 |
hex | 2c4c7292b |
11891321131 has 2 divisors, whose sum is σ = 11891321132. Its totient is φ = 11891321130.
The previous prime is 11891321087. The next prime is 11891321207. The reversal of 11891321131 is 13112319811.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11891321131 - 215 = 11891288363 is a prime.
It is a super-3 number, since 3×118913211313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 11891321093 and 11891321102.
It is not a weakly prime, because it can be changed into another prime (11891321231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5945660565 + 5945660566.
It is an arithmetic number, because the mean of its divisors is an integer number (5945660566).
Almost surely, 211891321131 is an apocalyptic number.
11891321131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11891321131 is an equidigital number, since it uses as much as digits as its factorization.
11891321131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296, while the sum is 31.
The spelling of 11891321131 in words is "eleven billion, eight hundred ninety-one million, three hundred twenty-one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •