Base | Representation |
---|---|
bin | 110111010111111101… |
… | …0101110001000111011 |
3 | 102100221102112110220111 |
4 | 1232233322232020323 |
5 | 3422014333220011 |
6 | 130343512205151 |
7 | 11406560161156 |
oct | 1565772561073 |
9 | 370842473814 |
10 | 118915523131 |
11 | 46482792649 |
12 | 1b0686997b7 |
13 | b2a1610192 |
14 | 5a812c8c9d |
15 | 315eb89121 |
hex | 1bafeae23b |
118915523131 has 2 divisors, whose sum is σ = 118915523132. Its totient is φ = 118915523130.
The previous prime is 118915523113. The next prime is 118915523159. The reversal of 118915523131 is 131325519811.
Together with previous prime (118915523113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 118915523131 - 221 = 118913425979 is a prime.
It is a super-2 number, since 2×1189155231312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (118915523101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59457761565 + 59457761566.
It is an arithmetic number, because the mean of its divisors is an integer number (59457761566).
Almost surely, 2118915523131 is an apocalyptic number.
118915523131 is a deficient number, since it is larger than the sum of its proper divisors (1).
118915523131 is an equidigital number, since it uses as much as digits as its factorization.
118915523131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 32400, while the sum is 40.
The spelling of 118915523131 in words is "one hundred eighteen billion, nine hundred fifteen million, five hundred twenty-three thousand, one hundred thirty-one".
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