Base | Representation |
---|---|
bin | 10110001010100011… |
… | …11101101110001011 |
3 | 1010201022111012121121 |
4 | 23011101331232023 |
5 | 143332314133103 |
6 | 5244445020111 |
7 | 600613152304 |
oct | 130521755613 |
9 | 33638435547 |
10 | 11899755403 |
11 | 50571133a8 |
12 | 2381254637 |
13 | 11784668b3 |
14 | 80c5a57ab |
15 | 499a6d6bd |
hex | 2c547db8b |
11899755403 has 2 divisors, whose sum is σ = 11899755404. Its totient is φ = 11899755402.
The previous prime is 11899755383. The next prime is 11899755437. The reversal of 11899755403 is 30455799811.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11899755403 is a prime.
It is not a weakly prime, because it can be changed into another prime (11899755463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5949877701 + 5949877702.
It is an arithmetic number, because the mean of its divisors is an integer number (5949877702).
Almost surely, 211899755403 is an apocalyptic number.
11899755403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11899755403 is an equidigital number, since it uses as much as digits as its factorization.
11899755403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1360800, while the sum is 52.
The spelling of 11899755403 in words is "eleven billion, eight hundred ninety-nine million, seven hundred fifty-five thousand, four hundred three".
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