Base | Representation |
---|---|
bin | 1010110101010100101101… |
… | …1001010100010011111011 |
3 | 1120011200220122121010211111 |
4 | 2231111023121110103323 |
5 | 3030123124031133203 |
6 | 41155533423541151 |
7 | 2336361604006306 |
oct | 255251331242373 |
9 | 46150818533744 |
10 | 11911209239803 |
11 | 3882574100555 |
12 | 140457ba5a7b7 |
13 | 6852b7278623 |
14 | 2d2711537b3d |
15 | 159c87d0726d |
hex | ad54b6544fb |
11911209239803 has 2 divisors, whose sum is σ = 11911209239804. Its totient is φ = 11911209239802.
The previous prime is 11911209239773. The next prime is 11911209239821. The reversal of 11911209239803 is 30893290211911.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11911209239803 - 217 = 11911209108731 is a prime.
It is a super-2 number, since 2×119112092398032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11911209239893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5955604619901 + 5955604619902.
It is an arithmetic number, because the mean of its divisors is an integer number (5955604619902).
Almost surely, 211911209239803 is an apocalyptic number.
11911209239803 is a deficient number, since it is larger than the sum of its proper divisors (1).
11911209239803 is an equidigital number, since it uses as much as digits as its factorization.
11911209239803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 49.
The spelling of 11911209239803 in words is "eleven trillion, nine hundred eleven billion, two hundred nine million, two hundred thirty-nine thousand, eight hundred three".
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