Base | Representation |
---|---|
bin | 10110001110100100… |
… | …00111101010001001 |
3 | 1010210122201000110211 |
4 | 23013102013222021 |
5 | 143414414204122 |
6 | 5252045041121 |
7 | 601501543303 |
oct | 130722075211 |
9 | 33718630424 |
10 | 11933350537 |
11 | 5074079979 |
12 | 23905561a1 |
13 | 11823ca084 |
14 | 812c2c973 |
15 | 49c9a7877 |
hex | 2c7487a89 |
11933350537 has 2 divisors, whose sum is σ = 11933350538. Its totient is φ = 11933350536.
The previous prime is 11933350523. The next prime is 11933350553. The reversal of 11933350537 is 73505333911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11909575161 + 23775376 = 109131^2 + 4876^2 .
It is a cyclic number.
It is not a de Polignac number, because 11933350537 - 223 = 11924961929 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11933350537.
It is not a weakly prime, because it can be changed into another prime (11933350937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5966675268 + 5966675269.
It is an arithmetic number, because the mean of its divisors is an integer number (5966675269).
Almost surely, 211933350537 is an apocalyptic number.
It is an amenable number.
11933350537 is a deficient number, since it is larger than the sum of its proper divisors (1).
11933350537 is an equidigital number, since it uses as much as digits as its factorization.
11933350537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 127575, while the sum is 40.
The spelling of 11933350537 in words is "eleven billion, nine hundred thirty-three million, three hundred fifty thousand, five hundred thirty-seven".
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