11940769483 has 2 divisors, whose sum is σ = 11940769484. Its totient is φ = 11940769482.

The previous prime is 11940769429. The next prime is 11940769487. The reversal of 11940769483 is 38496704911.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11940769483 is a prime.

It is a super-2 number, since 2×11940769483² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11940769483.

It is not a weakly prime, because it can be changed into another prime (11940769487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5970384741 + 5970384742.

It is an arithmetic number, because the mean of its divisors is an integer number (5970384742).

Almost surely, 2^11940769483 is an apocalyptic number.

11940769483 is a deficient number, since it is larger than the sum of its proper divisors (1).

11940769483 is an equidigital number, since it uses as much as digits as its factorization.

11940769483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 52.

The spelling of 11940769483 in words is "eleven billion, nine hundred forty million, seven hundred sixty-nine thousand, four hundred eighty-three".