1194095041113 has 64 divisors (see below), whose sum is σ = 1854252207360. Its totient is φ = 677106459648.

The previous prime is 1194095041099. The next prime is 1194095041127. The reversal of 1194095041113 is 3111405904911.

It is an interprime number because it is at equal distance from previous prime (1194095041099) and next prime (1194095041127).

It is not a de Polignac number, because 1194095041113 - 2⁵ = 1194095041081 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is not an unprimeable number, because it can be changed into a prime (1194095041163) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 110018995 + ... + 110029847.

It is an arithmetic number, because the mean of its divisors is an integer number (28972690740).

Almost surely, 2^{1194095041113} is an apocalyptic number.

1194095041113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1194095041113 is a deficient number, since it is larger than the sum of its proper divisors (660157166247).

1194095041113 is a wasteful number, since it uses less digits than its factorization.

1194095041113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14938.

The product of its (nonzero) digits is 19440, while the sum is 39.

The spelling of 1194095041113 in words is "one trillion, one hundred ninety-four billion, ninety-five million, forty-one thousand, one hundred thirteen".