119413513973 has 4 divisors (see below), whose sum is σ = 128599168908. Its totient is φ = 110227859040.

The previous prime is 119413513931. The next prime is 119413514023. The reversal of 119413513973 is 379315314911.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 40936214929 + 78477299044 = 202327^2 + 280138^2 .

It is not a de Polignac number, because 119413513973 - 2¹⁰ = 119413512949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (119413513273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4592827448 + ... + 4592827473.

It is an arithmetic number, because the mean of its divisors is an integer number (32149792227).

Almost surely, 2^119413513973 is an apocalyptic number.

119413513973 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

119413513973 is a deficient number, since it is larger than the sum of its proper divisors (9185654935).

119413513973 is an equidigital number, since it uses as much as digits as its factorization.

119413513973 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9185654934.

The product of its digits is 306180, while the sum is 47.

The spelling of 119413513973 in words is "one hundred nineteen billion, four hundred thirteen million, five hundred thirteen thousand, nine hundred seventy-three".