Base | Representation |
---|---|
bin | 10110010000110101… |
… | …10011100101110011 |
3 | 1010211222120002002011 |
4 | 23020122303211303 |
5 | 143434303423401 |
6 | 5254005303351 |
7 | 602122523242 |
oct | 131032634563 |
9 | 33758502064 |
10 | 11952404851 |
11 | 5083903742 |
12 | 2396a04b57 |
13 | 118633bc0a |
14 | 81558c959 |
15 | 49e4bd451 |
hex | 2c86b3973 |
11952404851 has 2 divisors, whose sum is σ = 11952404852. Its totient is φ = 11952404850.
The previous prime is 11952404837. The next prime is 11952404899. The reversal of 11952404851 is 15840425911.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11952404851 is a prime.
It is not a weakly prime, because it can be changed into another prime (11952404801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5976202425 + 5976202426.
It is an arithmetic number, because the mean of its divisors is an integer number (5976202426).
Almost surely, 211952404851 is an apocalyptic number.
11952404851 is a deficient number, since it is larger than the sum of its proper divisors (1).
11952404851 is an equidigital number, since it uses as much as digits as its factorization.
11952404851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 40.
The spelling of 11952404851 in words is "eleven billion, nine hundred fifty-two million, four hundred four thousand, eight hundred fifty-one".
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