Base | Representation |
---|---|
bin | 10001011001001110001… |
… | …101011100100001000001 |
3 | 11020021022102101200020212 |
4 | 101121032031130201001 |
5 | 124041000120241214 |
6 | 2313041431043505 |
7 | 152233654222505 |
oct | 21311615344101 |
9 | 4207272350225 |
10 | 1195313055809 |
11 | 420a250705a4 |
12 | 1737abb10595 |
13 | 88943578652 |
14 | 41bd3c78305 |
15 | 2115d4c153e |
hex | 1164e35c841 |
1195313055809 has 2 divisors, whose sum is σ = 1195313055810. Its totient is φ = 1195313055808.
The previous prime is 1195313055793. The next prime is 1195313055841. The reversal of 1195313055809 is 9085503135911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 998194815409 + 197118240400 = 999097^2 + 443980^2 .
It is a cyclic number.
It is not a de Polignac number, because 1195313055809 - 24 = 1195313055793 is a prime.
It is not a weakly prime, because it can be changed into another prime (1195313055109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 597656527904 + 597656527905.
It is an arithmetic number, because the mean of its divisors is an integer number (597656527905).
Almost surely, 21195313055809 is an apocalyptic number.
It is an amenable number.
1195313055809 is a deficient number, since it is larger than the sum of its proper divisors (1).
1195313055809 is an equidigital number, since it uses as much as digits as its factorization.
1195313055809 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 729000, while the sum is 50.
The spelling of 1195313055809 in words is "one trillion, one hundred ninety-five billion, three hundred thirteen million, fifty-five thousand, eight hundred nine".
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