11953424070 has 384 divisors, whose sum is σ = 39091092480. Its totient is φ = 2586608640.

The previous prime is 11953424053. The next prime is 11953424071. The reversal of 11953424070 is 7042435911.

11953424070 is a `hidden beast` number, since 1 + 19 + 534 + 2 + 40 + 70 = 666.

11953424070 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11953424071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 49599150 + ... + 49599390.

It is an arithmetic number, because the mean of its divisors is an integer number (101799720).

Almost surely, 2^11953424070 is an apocalyptic number.

11953424070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11953424070, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19545546240).

11953424070 is an abundant number, since it is smaller than the sum of its proper divisors (27137668410).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11953424070 is a wasteful number, since it uses less digits than its factorization.

11953424070 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 457 (or 444 counting only the distinct ones).

The product of its (nonzero) digits is 30240, while the sum is 36.

Adding to 11953424070 its reverse (7042435911), we get a palindrome (18995859981).

The spelling of 11953424070 in words is "eleven billion, nine hundred fifty-three million, four hundred twenty-four thousand, seventy".