Base | Representation |
---|---|
bin | 110111101010100011… |
… | …0111101100000000001 |
3 | 102102112220122012211221 |
4 | 1233111012331200001 |
5 | 3424304102120034 |
6 | 130525442035041 |
7 | 11431204614031 |
oct | 1572506754001 |
9 | 372486565757 |
10 | 119539488769 |
11 | 46772a1a228 |
12 | 1b201648a81 |
13 | b37097a20c |
14 | 5b0010d8c1 |
15 | 319983cbb4 |
hex | 1bd51bd801 |
119539488769 has 2 divisors, whose sum is σ = 119539488770. Its totient is φ = 119539488768.
The previous prime is 119539488749. The next prime is 119539488787. The reversal of 119539488769 is 967884935911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 69979824369 + 49559664400 = 264537^2 + 222620^2 .
It is a cyclic number.
It is not a de Polignac number, because 119539488769 - 231 = 117392005121 is a prime.
It is a super-2 number, since 2×1195394887692 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 119539488698 and 119539488707.
It is not a weakly prime, because it can be changed into another prime (119539488749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59769744384 + 59769744385.
It is an arithmetic number, because the mean of its divisors is an integer number (59769744385).
Almost surely, 2119539488769 is an apocalyptic number.
It is an amenable number.
119539488769 is a deficient number, since it is larger than the sum of its proper divisors (1).
119539488769 is an equidigital number, since it uses as much as digits as its factorization.
119539488769 is an evil number, because the sum of its binary digits is even.
The product of its digits is 117573120, while the sum is 70.
The spelling of 119539488769 in words is "one hundred nineteen billion, five hundred thirty-nine million, four hundred eighty-eight thousand, seven hundred sixty-nine".
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