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11955252416448 = 26311171947936587
BaseRepresentation
bin1010110111111000110010…
…0100101100111111000000
31120022220121002121100000010
42231332030210230333000
53031333324104311243
641232100034024520
72342511204562155
oct255761444547700
946286532540003
1011955252416448
11389a215352aa0
121411011a18140
136894b5b88cb3
142d48cca9822c
1515aeb4742433
hexadf8c92cfc0

11955252416448 has 448 divisors, whose sum is σ = 38541389414400. Its totient is φ = 3223408066560.

The previous prime is 11955252416447. The next prime is 11955252416479. The reversal of 11955252416448 is 84461425255911.

It is a Harshad number since it is a multiple of its sum of digits (57).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11955252416447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 326744011 + ... + 326780597.

Almost surely, 211955252416448 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11955252416448, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19270694707200).

11955252416448 is an abundant number, since it is smaller than the sum of its proper divisors (26586136997952).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11955252416448 is a wasteful number, since it uses less digits than its factorization.

11955252416448 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37128 (or 37118 counting only the distinct ones).

The product of its digits is 13824000, while the sum is 57.

The spelling of 11955252416448 in words is "eleven trillion, nine hundred fifty-five billion, two hundred fifty-two million, four hundred sixteen thousand, four hundred forty-eight".