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119558219953 is a prime number
BaseRepresentation
bin110111101011000111…
…0011010100010110001
3102102121012212212012111
41233112032122202301
53424323401014303
6130531351325321
711431523046634
oct1572616324261
9372535785174
10119558219953
1146782553247
121b207980841
13b374807c63
145b027c7c1b
15319b2dcb6d
hex1bd639a8b1

119558219953 has 2 divisors, whose sum is σ = 119558219954. Its totient is φ = 119558219952.

The previous prime is 119558219933. The next prime is 119558219999. The reversal of 119558219953 is 359912855911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63233640369 + 56324579584 = 251463^2 + 237328^2 .

It is a cyclic number.

It is not a de Polignac number, because 119558219953 - 225 = 119524665521 is a prime.

It is a super-4 number, since 4×1195582199534 (a number of 45 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (119558219933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59779109976 + 59779109977.

It is an arithmetic number, because the mean of its divisors is an integer number (59779109977).

Almost surely, 2119558219953 is an apocalyptic number.

It is an amenable number.

119558219953 is a deficient number, since it is larger than the sum of its proper divisors (1).

119558219953 is an equidigital number, since it uses as much as digits as its factorization.

119558219953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4374000, while the sum is 58.

The spelling of 119558219953 in words is "one hundred nineteen billion, five hundred fifty-eight million, two hundred nineteen thousand, nine hundred fifty-three".