Base | Representation |
---|---|
bin | 10110010001010010… |
… | …00111111010100001 |
3 | 1010212020121202120212 |
4 | 23020221013322201 |
5 | 143441234024423 |
6 | 5254221543505 |
7 | 602166444554 |
oct | 131051077241 |
9 | 33766552525 |
10 | 11956158113 |
11 | 5085a37609 |
12 | 2398114b95 |
13 | 1187054393 |
14 | 815c8869b |
15 | 49e9b0578 |
hex | 2c8a47ea1 |
11956158113 has 2 divisors, whose sum is σ = 11956158114. Its totient is φ = 11956158112.
The previous prime is 11956158091. The next prime is 11956158131. The reversal of 11956158113 is 31185165911.
Together with next prime (11956158131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7360267264 + 4595890849 = 85792^2 + 67793^2 .
It is a cyclic number.
It is not a de Polignac number, because 11956158113 - 210 = 11956157089 is a prime.
It is not a weakly prime, because it can be changed into another prime (11956158143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5978079056 + 5978079057.
It is an arithmetic number, because the mean of its divisors is an integer number (5978079057).
Almost surely, 211956158113 is an apocalyptic number.
It is an amenable number.
11956158113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11956158113 is an equidigital number, since it uses as much as digits as its factorization.
11956158113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 32400, while the sum is 41.
The spelling of 11956158113 in words is "eleven billion, nine hundred fifty-six million, one hundred fifty-eight thousand, one hundred thirteen".
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