Search a number
-
+
119672256286313 is a prime number
BaseRepresentation
bin11011001101011101011110…
…010100110100111001101001
3120200201120000022011022202222
4123031131132110310321221
5111141202240102130223
61102304401531403425
734131015033451043
oct3315353624647151
9520646008138688
10119672256286313
113514979a908215
12115093505b3575
1351a1078814143
14217a24d412a93
15dc7e3b4a70c8
hex6cd75e534e69

119672256286313 has 2 divisors, whose sum is σ = 119672256286314. Its totient is φ = 119672256286312.

The previous prime is 119672256286301. The next prime is 119672256286357. The reversal of 119672256286313 is 313682652276911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89621116386649 + 30051139899664 = 9466843^2 + 5481892^2 .

It is a cyclic number.

It is not a de Polignac number, because 119672256286313 - 218 = 119672256024169 is a prime.

It is a super-2 number, since 2×1196722562863132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (119672256286213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59836128143156 + 59836128143157.

It is an arithmetic number, because the mean of its divisors is an integer number (59836128143157).

Almost surely, 2119672256286313 is an apocalyptic number.

It is an amenable number.

119672256286313 is a deficient number, since it is larger than the sum of its proper divisors (1).

119672256286313 is an equidigital number, since it uses as much as digits as its factorization.

119672256286313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 39191040, while the sum is 62.

The spelling of 119672256286313 in words is "one hundred nineteen trillion, six hundred seventy-two billion, two hundred fifty-six million, two hundred eighty-six thousand, three hundred thirteen".