Base | Representation |
---|---|
bin | 10001011010101010000… |
… | …010011100110001101001 |
3 | 11020102021210100100102221 |
4 | 101122222002130301221 |
5 | 124102124020132121 |
6 | 2313454343554041 |
7 | 152320102254112 |
oct | 21325202346151 |
9 | 4212253310387 |
10 | 1196853677161 |
11 | 42164577618a |
12 | 173b5ba5b921 |
13 | 88b2a7c120c |
14 | 41cdc713209 |
15 | 211ed891b41 |
hex | 116aa09cc69 |
1196853677161 has 2 divisors, whose sum is σ = 1196853677162. Its totient is φ = 1196853677160.
The previous prime is 1196853677101. The next prime is 1196853677183. The reversal of 1196853677161 is 1617763586911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 664296721936 + 532556955225 = 815044^2 + 729765^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1196853677161 is a prime.
It is a super-3 number, since 3×11968536771613 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1196853677161.
It is not a weakly prime, because it can be changed into another prime (1196853677101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 598426838580 + 598426838581.
It is an arithmetic number, because the mean of its divisors is an integer number (598426838581).
Almost surely, 21196853677161 is an apocalyptic number.
It is an amenable number.
1196853677161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1196853677161 is an equidigital number, since it uses as much as digits as its factorization.
1196853677161 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11430720, while the sum is 61.
The spelling of 1196853677161 in words is "one trillion, one hundred ninety-six billion, eight hundred fifty-three million, six hundred seventy-seven thousand, one hundred sixty-one".
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