11975421953 has 4 divisors (see below), whose sum is σ = 13064096688. Its totient is φ = 10886747220.

The previous prime is 11975421949. The next prime is 11975421959. The reversal of 11975421953 is 35912457911.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35912457911 = 11 ⋅3264768901.

It is a cyclic number.

It is not a de Polignac number, because 11975421953 - 2² = 11975421949 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11975421898 and 11975421907.

It is not an unprimeable number, because it can be changed into a prime (11975421959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 544337351 + ... + 544337372.

It is an arithmetic number, because the mean of its divisors is an integer number (3266024172).

Almost surely, 2^11975421953 is an apocalyptic number.

It is an amenable number.

11975421953 is a deficient number, since it is larger than the sum of its proper divisors (1088674735).

11975421953 is a wasteful number, since it uses less digits than its factorization.

11975421953 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1088674734.

The product of its digits is 340200, while the sum is 47.

The spelling of 11975421953 in words is "eleven billion, nine hundred seventy-five million, four hundred twenty-one thousand, nine hundred fifty-three".