11979433 has 2 divisors, whose sum is σ = 11979434. Its totient is φ = 11979432.

The previous prime is 11979391. The next prime is 11979439. The reversal of 11979433 is 33497911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11812969 + 166464 = 3437^2 + 408^2 .

It is an emirp because it is prime and its reverse (33497911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11979433 - 2⁹ = 11978921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11979392 and 11979401.

It is not a weakly prime, because it can be changed into another prime (11979439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5989716 + 5989717.

It is an arithmetic number, because the mean of its divisors is an integer number (5989717).

Almost surely, 2^11979433 is an apocalyptic number.

It is an amenable number.

11979433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11979433 is an equidigital number, since it uses as much as digits as its factorization.

11979433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20412, while the sum is 37.

The square root of 11979433 is about 3461.1317513207. The cubic root of 11979433 is about 228.8119773935.

The spelling of 11979433 in words is "eleven million, nine hundred seventy-nine thousand, four hundred thirty-three".