Base | Representation |
---|---|
bin | 110111110010011010… |
… | …0000011010110011101 |
3 | 102110020021102022122201 |
4 | 1233210310003112131 |
5 | 3430324024424303 |
6 | 131011533211501 |
7 | 11440554264331 |
oct | 1574464032635 |
9 | 373207368581 |
10 | 119802967453 |
11 | 46898719704 |
12 | 1b275930b91 |
13 | b3b342b970 |
14 | 5b270d77c1 |
15 | 31b2a3581d |
hex | 1be4d0359d |
119802967453 has 16 divisors (see below), whose sum is σ = 131561051776. Its totient is φ = 108419912640.
The previous prime is 119802967451. The next prime is 119802967499. The reversal of 119802967453 is 354769208911.
It is a happy number.
It is not a de Polignac number, because 119802967453 - 21 = 119802967451 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 119802967394 and 119802967403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (119802967451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2601 + ... + 489502.
It is an arithmetic number, because the mean of its divisors is an integer number (8222565736).
It is a 1-persistent number, because it is pandigital, but 2⋅119802967453 = 239605934906 is not.
Almost surely, 2119802967453 is an apocalyptic number.
119802967453 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
119802967453 is a deficient number, since it is larger than the sum of its proper divisors (11758084323).
119802967453 is a wasteful number, since it uses less digits than its factorization.
119802967453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 492484.
The product of its (nonzero) digits is 3265920, while the sum is 55.
The spelling of 119802967453 in words is "one hundred nineteen billion, eight hundred two million, nine hundred sixty-seven thousand, four hundred fifty-three".
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