Base | Representation |
---|---|
bin | 1010111001100001101100… |
… | …0011000101010111101011 |
3 | 1120102121021121212021212002 |
4 | 2232120123003011113223 |
5 | 3032314012103032344 |
6 | 41253034223241215 |
7 | 2344526064010235 |
oct | 256303303052753 |
9 | 46377247767762 |
10 | 11983412549099 |
11 | 3900155a824a2 |
12 | 141657074920b |
13 | 68c053012994 |
14 | 2d6000a0d255 |
15 | 15bab1a8a44e |
hex | ae61b0c55eb |
11983412549099 has 2 divisors, whose sum is σ = 11983412549100. Its totient is φ = 11983412549098.
The previous prime is 11983412549077. The next prime is 11983412549113. The reversal of 11983412549099 is 99094521438911.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11983412549099 - 240 = 10883900921323 is a prime.
It is not a weakly prime, because it can be changed into another prime (11983412549699) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991706274549 + 5991706274550.
It is an arithmetic number, because the mean of its divisors is an integer number (5991706274550).
Almost surely, 211983412549099 is an apocalyptic number.
11983412549099 is a deficient number, since it is larger than the sum of its proper divisors (1).
11983412549099 is an equidigital number, since it uses as much as digits as its factorization.
11983412549099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25194240, while the sum is 65.
The spelling of 11983412549099 in words is "eleven trillion, nine hundred eighty-three billion, four hundred twelve million, five hundred forty-nine thousand, ninety-nine".
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