Base | Representation |
---|---|
bin | 10110010100100101… |
… | …10011000011010101 |
3 | 1010221011202011022220 |
4 | 23022102303003111 |
5 | 144020332004200 |
6 | 5301051412553 |
7 | 602654062062 |
oct | 131222630325 |
9 | 33834664286 |
10 | 11983859925 |
11 | 509a638374 |
12 | 23a5454159 |
13 | 118ca0329b |
14 | 819819c69 |
15 | 4a21334a0 |
hex | 2ca4b30d5 |
11983859925 has 12 divisors (see below), whose sum is σ = 19813315200. Its totient is φ = 6391391920.
The previous prime is 11983859903. The next prime is 11983859933. The reversal of 11983859925 is 52995838911.
It is not a de Polignac number, because 11983859925 - 29 = 11983859413 is a prime.
It is a super-2 number, since 2×119838599252 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 79892325 + ... + 79892474.
It is an arithmetic number, because the mean of its divisors is an integer number (1651109600).
Almost surely, 211983859925 is an apocalyptic number.
11983859925 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11983859925 is a deficient number, since it is larger than the sum of its proper divisors (7829455275).
11983859925 is a wasteful number, since it uses less digits than its factorization.
11983859925 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159784812 (or 159784807 counting only the distinct ones).
The product of its digits is 6998400, while the sum is 60.
The spelling of 11983859925 in words is "eleven billion, nine hundred eighty-three million, eight hundred fifty-nine thousand, nine hundred twenty-five".
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