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11984424262 = 25992212131
BaseRepresentation
bin10110010100101001…
…11100110101000110
31010221012210211110021
423022110330311012
5144021003034022
65301111445354
7602661632266
oct131224746506
933835724407
1011984424262
11509a993368
1223a568685a
13118cb70105
148199257a6
154a21e57c7
hex2ca53cd46

11984424262 has 4 divisors (see below), whose sum is σ = 17976636396. Its totient is φ = 5992212130.

The previous prime is 11984424223. The next prime is 11984424281. The reversal of 11984424262 is 26242448911.

11984424262 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 26242448911 = 73748921273.

It is a super-2 number, since 2×119844242622 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2996106064 + ... + 2996106067.

It is an arithmetic number, because the mean of its divisors is an integer number (4494159099).

Almost surely, 211984424262 is an apocalyptic number.

11984424262 is a deficient number, since it is larger than the sum of its proper divisors (5992212134).

11984424262 is an equidigital number, since it uses as much as digits as its factorization.

11984424262 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5992212133.

The product of its digits is 221184, while the sum is 43.

The spelling of 11984424262 in words is "eleven billion, nine hundred eighty-four million, four hundred twenty-four thousand, two hundred sixty-two".

Divisors: 1 2 5992212131 11984424262