Base | Representation |
---|---|
bin | 10110010100101100… |
… | …10001001110011011 |
3 | 1010221020110101122102 |
4 | 23022112101032123 |
5 | 144021100114242 |
6 | 5301123114015 |
7 | 602664602153 |
oct | 131226211633 |
9 | 33836411572 |
10 | 11984769947 |
11 | 50a00aa057 |
12 | 23a581290b |
13 | 118cc61567 |
14 | 8199b5763 |
15 | 4a2262e32 |
hex | 2ca59139b |
11984769947 has 2 divisors, whose sum is σ = 11984769948. Its totient is φ = 11984769946.
The previous prime is 11984769899. The next prime is 11984769961. The reversal of 11984769947 is 74996748911.
11984769947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11984769947 - 28 = 11984769691 is a prime.
It is not a weakly prime, because it can be changed into another prime (11984769997) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5992384973 + 5992384974.
It is an arithmetic number, because the mean of its divisors is an integer number (5992384974).
Almost surely, 211984769947 is an apocalyptic number.
11984769947 is a deficient number, since it is larger than the sum of its proper divisors (1).
11984769947 is an equidigital number, since it uses as much as digits as its factorization.
11984769947 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 27433728, while the sum is 65.
The spelling of 11984769947 in words is "eleven billion, nine hundred eighty-four million, seven hundred sixty-nine thousand, nine hundred forty-seven".
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