Base | Representation |
---|---|
bin | 10001011100001010111… |
… | …101110001001101100111 |
3 | 11020120111010020222122001 |
4 | 101130022331301031213 |
5 | 124113441314340403 |
6 | 2314323554150131 |
7 | 152405306362000 |
oct | 21341275611547 |
9 | 4216433228561 |
10 | 1198479840103 |
11 | 4222aa6974a7 |
12 | 174334582347 |
13 | 89029687600 |
14 | 420146981a7 |
15 | 2129650cc1d |
hex | 1170af71367 |
1198479840103 has 36 divisors (see below), whose sum is σ = 1513758212400. Its totient is φ = 948039241968.
The previous prime is 1198479840049. The next prime is 1198479840113. The reversal of 1198479840103 is 3010489748911.
It is a happy number.
It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.
It is a de Polignac number, because none of the positive numbers 2k-1198479840103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1198479840113) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 263573676 + ... + 263578222.
Almost surely, 21198479840103 is an apocalyptic number.
1198479840103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1198479840103 is a deficient number, since it is larger than the sum of its proper divisors (315278372297).
1198479840103 is an frugal number, since it uses more digits than its factorization.
1198479840103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9141 (or 4567 counting only the distinct ones).
The product of its (nonzero) digits is 1741824, while the sum is 55.
The spelling of 1198479840103 in words is "one trillion, one hundred ninety-eight billion, four hundred seventy-nine million, eight hundred forty thousand, one hundred three".
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